Question

A motorcycle is moving with a velocity of 72 km/hr and it takes 6 seconds to stop it, after the brakes are applied. Calculate the force exerted by the brakes, on the motorcycle , if its mass along with the rider is 300 kg.​

Answer 1

Answer:

First change the km/hr to m/s

First change the km/hr to m/sSo 72 km/hr ----->  20m/s

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/s

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/s

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/sTime taken to stop=t=6s

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/sTime taken to stop=t=6sMass of the motorcycle=175kg

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/sTime taken to stop=t=6sMass of the motorcycle=175kgForce = Mass * Acceleration

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/sTime taken to stop=t=6sMass of the motorcycle=175kgForce = Mass * AccelerationMass = 175 kg

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/sTime taken to stop=t=6sMass of the motorcycle=175kgForce = Mass * AccelerationMass = 175 kgAcceleration=Rate of change of velocity/time=v-u/t=0-20/6=-10/3m/s^2

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/sTime taken to stop=t=6sMass of the motorcycle=175kgForce = Mass * AccelerationMass = 175 kgAcceleration=Rate of change of velocity/time=v-u/t=0-20/6=-10/3m/s^2Force = 175 * -10/3=-583.334 Newton

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/sTime taken to stop=t=6sMass of the motorcycle=175kgForce = Mass * AccelerationMass = 175 kgAcceleration=Rate of change of velocity/time=v-u/t=0-20/6=-10/3m/s^2Force = 175 * -10/3=-583.334 Newton(the negatice sign indicates negative force)

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/sTime taken to stop=t=6sMass of the motorcycle=175kgForce = Mass * AccelerationMass = 175 kgAcceleration=Rate of change of velocity/time=v-u/t=0-20/6=-10/3m/s^2Force = 175 * -10/3=-583.334 Newton(the negatice sign indicates negative force)Hope this helps you

First change the km/hr to m/sSo 72 km/hr ----->  20m/sInitial velocity=u=20m/sFinal velocity=v=0m/sTime taken to stop=t=6sMass of the motorcycle=175kgForce = Mass * AccelerationMass = 175 kgAcceleration=Rate of change of velocity/time=v-u/t=0-20/6=-10/3m/s^2Force = 175 * -10/3=-583.334 Newton(the negatice sign indicates negative force)Hope this helps youIf you find this helpful then pls mark it as the brainliest