Question

A motorcycle is moving with a velocity of 90 km h^-1 and it takes 5 seconds to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcycle if its mass along with the rider is 200 kg.​

Answer 1

Answer:

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Questiong ⤵

A motorcycle is movging with a velocity of 90 km h^-1 and it takes 5 seconds to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcycle if its mass along with the rider is 200 kg

Answer ⤵

f= -1000N

Given

➡initial velocity u=90km/h or 90×5/18=25m/s

➡final velocity v=0m/s

➡time t=5s

➡mass m=200kg

to ask

➡force exerted by brakes f

➡first we find out acceleration a

$</p><p>by \: using \: 1st \: eqution \: of \: motion \\ v - u = at \: \\ so \: \: \: \: a = \frac{v - u}{t} \\ a = \frac{0 - 25}{5} \\ a = \frac{ - 25}{5} \\ a = ( - 5)m {s}^{ - 2} \\ now \: using \: f = ma \\ f = 200kg \times ( - 5)m {s}^{ - 2} \\ f = ( - 1000)kgm {s}^{ - 2} \\ or \: f = ( - 1000)newton$

Note: Here negative force is the symbol of retardation. Breakes applies opposite force by which the motorcycle is stop. Force applied by brakes is opposite direction so force is negative.

when motorcycle is moving with a velocity of 90 km h^-1 and it takes 5 seconds to stop after the brakes are applied. if its mass along with the rider is 200 kg. Then the force exerted by the brakes on motorcycles is (-1000) N.

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Answer 2

Explanation:

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