Question

A motorcycle is moving with a velocity of 90 km/h and it takes 5 seconds to stop after the brakes are applied. calculate the force exerted by the brakes on the brakes on the motorcycle if its mass along with the rider is 200kg

Answer 1

initial velocity(u) = 90km/h
= 25m/s
Final velocity(v) = 0 (as it comes to rest)
Time taken (t) = 5s

using 1st equation of motion

acceleration (a)= (v-u)/t
= (0 - 25)/ 5
= -25/5
= -5 m/s^2

mass of the motorcycle along with the rider = 200kg

so, the force applied by the body
= 200 × (-5)
= -1000N

Answer 2

initial velocity=90km/h

=25m/s

final velocity=0

total time taken=5 second

from 1 equation of motion

a=v-u/t

a=0-25/5

=-25/5

=-5

now,the force exerted by brakes

=200×(-5)

=-1000N

the force exerted by brakes is -1000N

Hope it's help you

PLS Mark me as a brainlist