Question

A motorcycle is moving with a velocity of 90 km/h and it takes 5 second to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcycle if its mass along with the rider is 200 kg. Find out the Force in Dyne ?

Answer 1

ANSWER :-

Mass of motorcycle, m = 200 kg

Initial velocity, u = 90 km/hr = 90 * 5/18 = 25 m/s

Final velocity, v = 0 m/s

time, t = 5 sec

Acceleration, a = v-u/t = 0-25/5 = -5 m/s²

According to newton 's Second Law of Motion,

F = ma = 200 kg * -5 m/s² = -1000 N

Therefore the force exerted by the brakes is -1000 N .

Or

Using the equation of motion v = u+at

v = 90 km/h = 25 m/s

0 = 25+5a

-25 = 5a

-25/5 = a

a = -5

now,F = ma

F = 200 x -5

F= -1000N

__________________

HARSH PRATAP SINGH

Answer 2

$\huge\red{Answer}$

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• Initial velocity, u = 90 km/h or 25 m/s.

• Now, force exerted by the brakes will be the acceleration they produce to stop the motorcycle.

• Therefore, force exerted by the brakes is -1000 N to stop the motorcycle.

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