Question

A motorcycle is moving with the velocity of 90 km per hour and it takes 55 second to stop after the brakes are applied calculate the force exerted by the brakes on the motorcycle if its mass along with the rider is 200 kg

Answer 1

vi=90km=150m/s

vf=0m/s

t=55s

a=vf-vi/t

a=0-150/55

a=-2.72

as F=ma

F=200x-2.72

F=-544

as force is never negative, hence

F=544N

Answer 2

Answer:

${ \huge{\boxed{\tt {\color{red}{Answer}}}}}$

Answer:

Given :-

A motorcycle is moving with a velocity of 90 km/h and its takes 5 seconds to stop after the brakes are applied and its mass along the rider is 200 kg.

To Find :-

How much force exerted by the brakes on the motorcycle.

Formula Used :-

❶ To find acceleration we know that,

✦ a = v - u/t ✦

where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

❷ To find force we know that,

❖ F = ma ❖

where,

F = Force

m = Mass

a = Acceleration

Solution :-

❶ First we have to find the acceleration,

Given :

v = 0 m/s

u = 90 km/h = 90 × 5 ÷ 18 m/s = 25 m/s

t = 5 seconds

According to the question by using the formula we get,

⇒ a = 0 - 25/5

⇒a = - 25/5

➠ a = - 5 m/s²

Hence, acceleration is - 5 m/s² .

❷ Now we have to find the force,

We get,

Mass = 200 kg

Acceleration = - 5 m/s

According to the question by using the formula we get,

↦ F = 200 × - 5

➥ F = - 1000 N

∴ The force exerted by the brakes on the motorcycle is - 1000 N .