a motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. calculate the speed of the motorcycle after 10 seconds,and the distance travelled in this time.
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28
u=5m/s
a=0.2m/s²
u=?
t=10 s
and s =?
according to 1st equation of motion
v= u + at
5 +0.2(10)
=5+2
=7 m/s
according to the 2nd equation of motion
s=ut+1/2 at²
=5(10)+1/2*0.2*10
=50+1/2*20
= 50+10
=60
a=0.2m/s²
u=?
t=10 s
and s =?
according to 1st equation of motion
v= u + at
5 +0.2(10)
=5+2
=7 m/s
according to the 2nd equation of motion
s=ut+1/2 at²
=5(10)+1/2*0.2*10
=50+1/2*20
= 50+10
=60
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4
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