Question

A motorcycle moving with a speed of 5m per s is subjected to an acceleration of 0.2m per s calculate the speed of the motorcycle after 10sec. And the distance traveled in this time

Answer 1

initial speed of car=5 m/s

accl=0.2m/s2

time=10s

distance=?

 

solution: s= ut+1/2at2

              s=(5)(10)+1/2 (0.2)(10)(10)

                  (50)+1/2(20)

                  =(50)+(10)

                  =60m

 

There’s an alternate method too:

u = 5 m/s

a = 0.2 m/s²

t = 10 seconds

v = u + at

= 5 + 0.2×10

= 5+2

= 7 m/s

s = ut + 1/2at²

= (5×10) + (1/2)×(2/10)×(10×10)

= 50 + 10

= 60 m

Final speed = 7 m/s

Distance travelled in 10 seconds = 60 m

Even this ones nice method:

u = 5 m/sec

a = 0.2 m/sec ^ 2

t = 10 sec

USING 1ST EQ OF MOTION,

v = u + at

v = 5 + 0.2×10

v = 5 + 2

v = 7 m/sec

FINAL VELOCITY = 7 m/sec

2nd EQ OF MOTION,

s = ut + 1/2 at^2

s = 5 × 10 + 1/2 × 2/10×10×10

s = 50 + 10

s = 60m

DISTANCE = 60 m

I have provided uh with 3 methods, plz follow up with ur convinient one ;)

 

Hope This helps :)