A motorcycle moving with a speed of 5m/s is subjected to an acceleration of0.2m/s2. Calculate tha speed of the motorcycle after 10 seconds,and the distance travelled in this time.
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Answered by
1
U=5m/s
A=0.2m/s2
T=10s
According to Ist equation of motionwe have=v=u+at
v=5+0.2(10)
v=5+2
v=7
speed =7m/s
S=ut+1/2at*t
s=5(10)+1/2*0.2*10*10
s=50+10
s=60m
A=0.2m/s2
T=10s
According to Ist equation of motionwe have=v=u+at
v=5+0.2(10)
v=5+2
v=7
speed =7m/s
S=ut+1/2at*t
s=5(10)+1/2*0.2*10*10
s=50+10
s=60m
Answered by
0
Use newton's laws of motion
V=u+at (u ,a and t are given)
V=7m/s
Then use v2-u2=2as to find distance s=24/2*0.2=60m
V=u+at (u ,a and t are given)
V=7m/s
Then use v2-u2=2as to find distance s=24/2*0.2=60m
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