Question

A motorcycle of mass 2000 kg is moving over a horizontal road with uniform velocity. If this motorcycle as to be stopped with a negative acceleration of 1.5m/sec, then what is the force of friction between the tyres of motorcycle and the road?

Answer 1

acceleration, a = -1.5 m/s²
mass, m = 2000 kg

force = ma = 2000×(-1.5) = -3000N

So force is 3000N acting in the opposite direction to the motion.
(negative sign shows that it is acting opposite to the motion of object)

Answer 2

Answer:

Force of friction between the tyres of motorcycle and the road is - 3000N

Explanation:

Given:

Motorcycle of mass is 2000kg

Negative Acceleration of a cycle is 1.5 m/sec

To find: The force of friction between the tyres of motorcycle and the road

Solution:

Force:

• The force produced by two surfaces that come into contact and slide against one another is referred to as frictional force.
• According to force, an object's rate of change in velocity is directly proportional to the force used and moves in the direction of the applied force. 

 Force (N) = mass (kg) x acceleration (m/s2).

A constant mass item will therefore accelerate in direct proportion to the force applied.

Given that

Acceleration a = -1.5 $m/s^{2}$

Negative sign indicates the negative acceleration

Mass m = 2000 kg

As we know that

Force = acceleration × mass

           = 2000 × (-1.5)

           = - 3000 N

Negative sign indicates that it is acting opposite to the motion of the object

Force is 3000N acting in the opposite direction to the motion

Final answer:

Force of friction between the tyres of motorcycle and the road is - 3000N

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