a motorcycle us moving with a velocity of 90 km/hr and it takes 5 seconds to stop after the brakes applies. calculate the force exerted by the brakes on the motorcycle if it's mass along with the rider is 200kg
Answers
- Initial velocity , u = 90 km/h.
- Final velocity , v = 0 m/s.
- Time , t = 5 seconds.
- mass of body , m = 200 kg.
- The force exerted by the brakes on motorcycle , F.
Here, the final velocity (v) of the motorcycle is “ 0 ” . [Because, brakes are applied on the motorcycle .]
initial velocity (u) = 90km/h = 90 × 5/18 = 25m/s
Time (t) = 5s
[Note :- The -ve sign indicates the deacceleration of the motorcycle.]
⭐ According to Newton's 2nd law motion ,
mass = 200kg
The force exerted by the brakes is “ 1000N ”
A motorcycle moving with a velocity of 90km/hr and it takes 5 seconds to stop after the brakes applies. Calculate the force exerted by the brakes on the motorcycle if it's mass along the rider is 200kg?
Initial velocity=90km/hr.
mass=200kg
time=5 seconds
final velocity=0m/s
According to 1st equation of motion
v=u+at
0=25+a×5
0=25+5a
5a=-25
According to second law of motion
Force=mass×acceleration
Force=200×(-5)
Force=-1000N
A force of -1000N is being exerted.