Question

A motorcyclist ( as a particle ) is undergoing vertical circles inside a sphere of death . the speed of the motorcycle varies between 6 m/s and 10 m/s . calculate diameter of the sphere of death . how much minimum values are possible for these two speeds ?
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Answer 1

Explanation:

Given A motorcyclist ( as a particle ) is undergoing vertical circles inside a sphere of death . the speed of the motorcycle varies between 6 m/s  and 10 m/s . calculate diameter of the sphere of death . how much minimum values are possible for these two speeds ?

• Given speed of motorcycle varies between 6 m/s and 10 m/s
• By the law of conservation of energy we have
• 1/2 mv^2 + mgh = 1/2 mu^2
• 1/2 mv^2 – 1/2 mu^2 = - mgh
• Or 1/2 m (u^2 – v^) = mgh
• Or 1/2 (u^2 – v^2) = gh
• Or h = 1/2 (100 – 36 / 10)
• Or   h = 6.4 / 2
• Or h = 3.2 m  
• Or r = 3.2 / 2 = 1.6
• Now v min = √gr
•                    = √10 x 1.6
•                   = √16  
• Or v min = 4 m/s

Reference link will be

https://brainly.in/question/17065956

Answer 2

Answer:

(v¹)min=4m/s

(v²)min=4√5m/s]