Question

a motorcyclist drive from a and b with a uniform speed 30 km per hour return back with a speed of 20 km per hour .find its average speed

Answer 1

Lets suppose the time taken in moving from A to B is T1.

Speed = 30km/hr

So T1= AB/30

 

Lets suppose the time taken in moving from B to A is T2

Speed = 20 km/hr

T2 = AB/20

 

Total distance = 2AB

Total Time = AB/20 + AB/30

= AB [1/20 +1/30]

= AB [50/600]

=ABx 5/60

 

Average Speed = Total Distance / Total Time

= 2ABx60/ABx5 = 120/5 = 24 km/hr

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