A motorcyclist drives A and B with uniform speed of 30 kmph and return backs with a speed of 20 kmph. Find average speed
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Let the distance from A to B be z
While going; v=30km/h
s=(z)km
t= s/v = (z/30)h
While returning, v=20km/h
s=(z)km
t= (z/20)h
Therefpre average speed=
(z+z)km / (z/30+z/20)h
=24km/h
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