A motorcyclist drives from A to B uniform speed of 30 km/h and returns back with a speed of 20km/h. Find its average speed.
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Let distance between A and B is D
Then, time taken by motorcyclist with uniform speed 30 km/hr,T1 = Distance / speed = D/30hrs
Again,they return with uniform speed 20 km, so time taken by motorcyclist, T2= D/20 hrs
Now, average speed of motorcyclist = total distance / total time taken
= (D+D)/ ( D/30 + D/20)km/hrs
= 2 × 30 × 20 / ( 30+20)km/hr
= 24 km/ hr
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Then, time taken by motorcyclist with uniform speed 30 km/hr,T1 = Distance / speed = D/30hrs
Again,they return with uniform speed 20 km, so time taken by motorcyclist, T2= D/20 hrs
Now, average speed of motorcyclist = total distance / total time taken
= (D+D)/ ( D/30 + D/20)km/hrs
= 2 × 30 × 20 / ( 30+20)km/hr
= 24 km/ hr
HOPE!IT HELPS YOU
PLEASE MARK AS BRAINLIST
Answered by
2
Let distance between A and B is D
Then, time taken by motorcyclist with uniform speed 30 km/hr,T1 = Distance / speed = D/30hrs
Again,they return with uniform speed 20 km, so time taken by motorcyclist, T2= D/20 hrs
Now, average speed of mot
Read more on Brainly.in - https://brainly.in/question/4273578#readmore
Then, time taken by motorcyclist with uniform speed 30 km/hr,T1 = Distance / speed = D/30hrs
Again,they return with uniform speed 20 km, so time taken by motorcyclist, T2= D/20 hrs
Now, average speed of mot
Read more on Brainly.in - https://brainly.in/question/4273578#readmore
dakuraosahab:
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