A motorcyclist drives from a to b with a uniform speed of 30 km per hour and returns back with a speed of 20 km per hour find its average speed
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Hey friend!!!
Let distance between A and B is D
Then, time taken by motorcyclist with uniform speed 30 km/h ,
T₁ = distance/speed = D/30 hrs
Again, they return with uniform speed 20 km , so time taken by motorcyclist ,
T₂ = D/20 hrs
Now, average speed of motorcyclist = total distance/total time taken
= (D + D )/(D/30 + D/20) km/h
= 2 × 30 × 20/(30 + 20) km/h
= 24 km/h______answer
hope it will help you..
Let distance between A and B is D
Then, time taken by motorcyclist with uniform speed 30 km/h ,
T₁ = distance/speed = D/30 hrs
Again, they return with uniform speed 20 km , so time taken by motorcyclist ,
T₂ = D/20 hrs
Now, average speed of motorcyclist = total distance/total time taken
= (D + D )/(D/30 + D/20) km/h
= 2 × 30 × 20/(30 + 20) km/h
= 24 km/h______answer
hope it will help you..
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