a motorcyclist drives from the place A to B with uniform speed of 30 km per hour and returns from place B to A with a uniform speed of 20 km per hour find its average speed
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Hey
(A)●------------------------------------●(B)
Suppose that the body covered the distance from A to B
Let the distance between those two points be d
Speed1 = 30km/h
Time 1 = distance / speed
= d/30 h
Speed while returning = 20km
Time 2 = d/20 h
Average speed = total distance covered / total time taken
=( d+d) ÷ (d/20) +(d/30)
= 2d ÷ (3d+2d) / 60
= (12)(2)
= 24
So, the average speed was 24 km/h.
Hope it helps to you.
(A)●------------------------------------●(B)
Suppose that the body covered the distance from A to B
Let the distance between those two points be d
Speed1 = 30km/h
Time 1 = distance / speed
= d/30 h
Speed while returning = 20km
Time 2 = d/20 h
Average speed = total distance covered / total time taken
=( d+d) ÷ (d/20) +(d/30)
= 2d ÷ (3d+2d) / 60
= (12)(2)
= 24
So, the average speed was 24 km/h.
Hope it helps to you.
uutkarshsonii:
Heya
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