a motorcyclist is runing on a circular track of radius 6 meter at the rate of 70 km per hour .through what angle will it turn in 5 second?
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Answer:
he will turn in a acute angle
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70km/hr = 350/18 m/sec
Circumference= 2πr= 2×22/7×6= 264/7m
Distance covered in 5 seconds= 350/18 × 5 m
Angle covered in 5 seconds
= [350×5/ 18]÷[264/7] ×360°
= (350×5× 7)/(18×264) × 360°
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