A motorcyclist rounds a curve of radius 25 m at 36 km/hr .The combined mass of motorcyclist and the man is 150 kg. what is the centripetal force exerted on theMotorcyclist
Answers
Solution :-
As per the given data ,
- Radius of the curve(r) = 25 m
- Speed(v) = 36 km / hr
In order to convert km / hr into m / s multiply by 5 / 18
Hence ,
Speed = 36 x 5 / 18 = 10 m /s
- Mass of the motorcyclist (m) = 150 kg
A body moves in circular motion due to the centripetal force acting on it towards the center
The centripetal force is given by the formula ,
➽ F = m v² / r
Now let's substitute the given values in the above equation ,
➽ F = 150 x 100 / 25
➽ F = 150 x 4
➽ F = 600 N
The centripetal force exerted on the motorcyclist is 600 N
Answer:
The centripetal force exerted on the motorcyclist exists 600 N.
Explanation:
A centripetal force exists as a force that creates a body following a curved path. Its direction exists always orthogonal to the motion of the body and towards the fixed point of the instantaneous center of curvature of the path.
As per the provided data,
- Radius of the curve(r) = 25 m
- Speed(v) = 36 km / hr
In order to transform km / hr into m / s multiply by 5 / 18
Therefore,
Speed = 36 x 5 / 18 = 10 m /s
Mass of the motorcyclist (m) = 150 kg
A body moves in a circular motion due to the centripetal force operating on it towards the center
The centripetal force exists provided by the formula,
F = m v² / r
Now let's substitute the conveyed values in the above equation,
F = 150 x 100 / 25
F = 150 x 4
F = 600 N
The centripetal force exerted on the motorcyclist exists 600 N.
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