a motorcyclist start from rest and reaches a speed of 6 meter per second after travelling with uniform acceleration for 3 second what is his acceleration
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Answered by
1
a=v-u/t
Here v=6 m/s
u=0
t=3sec
a=6-0/3
=2m/s^2
Here v=6 m/s
u=0
t=3sec
a=6-0/3
=2m/s^2
Answered by
0
initial velocity,u = 0 m/s
final velocity, v = 6m/s
time ,t= 3sec
acceleration = v-u/t
6-0/3
6/3
2m/s^2
final velocity, v = 6m/s
time ,t= 3sec
acceleration = v-u/t
6-0/3
6/3
2m/s^2
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