A motorcyclist starts from rest and reaches a speed of 6 m/s after travelling with uniform acceleration for 3s. What is his acceleration?
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Answered by
10
initial velocity "u"=0
final velocity"v"=6
time taken "t"=3s
acceleration "a"=(v-u)/t
=(6-0)/3
=6/3
2m/s^2
final velocity"v"=6
time taken "t"=3s
acceleration "a"=(v-u)/t
=(6-0)/3
=6/3
2m/s^2
Answered by
2
2m/s^2 is the answer to this question
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