Question

A motorcyclist starts from rest and reaches a speed of 6m/s after travelling with uniform acceleration for 3s . What is his acceleration?

Answer 1

We know that a = (v-u)/t where a is acceleration, v is the final velocity, u is the initial velocity and t is time.
v = 6m/s
u = 0m/s (as the body starts from rest)
t = 3s
a = ?

Substituting for the equation I already typed above, we have a = (6-0)/3 = 6/3 = 2
Therefore, the acceleration is 2m/s2
Hope this helps.

Answer 2

Answer:

We know, a= V-U/t

where, a is acceleration, v is the final velocity, u is the initial velocity and t is time.

v = 6 m/s

u = 0 m/s (as the body starts from rest)

t = 3s

a = ?

Substituting the values, we get, a = (6-0)/3

= 2m/s2

Therefore, the acceleration is 2m/s2