The difference between the ages of two cousins is 10 years. 15 years ago, if the one was twice as old as the younger one, find their present age
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Answered by
3
Let the ages of the cousins be x & y respectively
x-y=10
(x-15)=2 (y-15)
solving these equations we get y=25 and x=35
x-y=10
(x-15)=2 (y-15)
solving these equations we get y=25 and x=35
Answered by
3
Let The Age Be a & b.
a - b = 10.
( a - 15 ) = 2 ( b - 15 ).
a - 15 = 2b - 30
b = 25.
a = 35.
Answer............................
a - b = 10.
( a - 15 ) = 2 ( b - 15 ).
a - 15 = 2b - 30
b = 25.
a = 35.
Answer............................
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