A motorcyclist wants to drive on the vertical surface of a wooden well of radius 5m with a minimum speed of 5√5 The minimum value of coefficient of friction between the tyres and the wall of the well must be?
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Frictional force = f = mg
Centripetal Force = Contact force = N = mv² / r
μ = f / N
= mg / (mv^2 / r)
= rg / v²
= (5 × 10) / (5√5)²
= 50 / 125
= 0.4
Minimum coefficient of friction between the tyres and wall of the well must be 0.4
Centripetal Force = Contact force = N = mv² / r
μ = f / N
= mg / (mv^2 / r)
= rg / v²
= (5 × 10) / (5√5)²
= 50 / 125
= 0.4
Minimum coefficient of friction between the tyres and wall of the well must be 0.4
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