A motorist starts from rest and reaches a speed of 6 m/s after travelling with uniform acceleration for 3 sec. what is his acceleration.
Answers
Answered by
2
we know that acceleration =final velocity-initial velocity/time
here,
final velocity=6 m/s
initial velocity=0 m/s (as he was at rest)
time =3 sec
acceleration=6-0/3
=6/3
=2 m/s²
here,
final velocity=6 m/s
initial velocity=0 m/s (as he was at rest)
time =3 sec
acceleration=6-0/3
=6/3
=2 m/s²
Answered by
1
given that,
final velocity (v) = 6 m/s
initial velocity (u) = 0 m/s
time taken= seconds.
now,
we know that acceleration (a) is the rate of change of velocity in unit tme.
therefore,
a= (v-u)/ t
= (6-0) / 3
=6/ 3
= 2 m/s²
thank you.....
final velocity (v) = 6 m/s
initial velocity (u) = 0 m/s
time taken= seconds.
now,
we know that acceleration (a) is the rate of change of velocity in unit tme.
therefore,
a= (v-u)/ t
= (6-0) / 3
=6/ 3
= 2 m/s²
thank you.....
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