a motorist travelled from town A To Town b at an average speed of 54 km per hour on his return journey his average speed was 60 km per hour if the speed total time taken is 9 1/2 hours find the distance between the two towns
Answers
Answered by
24
Answer:
Let the distance between the town A and B =X
Total Time =
X/54 + X/ 60 = 19/20
10x +9x /540 = 19 / 2
20x+ 18x = 19 × 540
38x = 10260
X = 10260/38
X = 270 Ans.
Distance between Town A and Town B = 270
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@GauravSaxena01
Let the distance between the town A and B =X
Total Time =
X/54 + X/ 60 = 19/20
10x +9x /540 = 19 / 2
20x+ 18x = 19 × 540
38x = 10260
X = 10260/38
X = 270 Ans.
Distance between Town A and Town B = 270
=================
@GauravSaxena01
Answered by
0
Answer: x= 63
Step-by-step explanation:
Let the speed of one motorcycle1 be x.
Then motorcycle2 will be x+7 ((7 kmph faster))
AFTER TWO HOURS
Motorcycle1: 2×x
Motorcycle2: 2×x+7
2x + 2(x+7)+ 34 =300
2x + 2x+14 + 34=300
4x + 48 =300
4x= 300- 48
4x= 252
x= 252÷4
x= 63
Therefore motorcycle1 is at a speed of 63kmph while motorcycle2 is at a speed of 63+7=70 kmph.
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