A motorist travels to a place 150 km away at and average speed of 50km/hour and returns at 30km/hour. What is the average speed for the whole journey
Answers
the average speed for the whole journey is 37.5
Answer:
Avg. Speed for the whole Journey = 37.5 km/h
Step-by-step explanation:
We can solve it in two ways
Method 1 (Long process)
We know that,
Avg. Speed
= Total Distance covered/Total Time taken
Now,
Total Distance = 150 km + 150 km
Because he went to the destination and came back to the same point.
Total Distance = 300 km
Now, we know that,
Speed = Distance/Time
Then,
Time = Distance/Speed
Now,
Time taken from point A to destination = 150/50
T1 = 3 hrs
Time taken from destination to point A = 150/30
T2 = 5 hrs
Total Time taken = T1 + T2
= 3 + 5
= 8 hrs
So,
Avg. Speed
= Total Distance covered/Total Time taken
Avg. Speed = 300/8
= 150/4
= 75/2
= 37.5 km/h
Hence,
Avg. Speed for the whole Journey = 37.5 km/h
Method 2 (Easy substitution)
We should know that,
Avg. Speed = 2(S1)(S2)/[S1 + S2]
Here, let's just prove it and see what we get, it definitely easier this way
So,
Let the distance from point A to destination be D
Then,
Total Distance = Distance from point A to destination + Destination to Point A
Total Distance = D + D = 2D
Now,
Let the Average speed taken during the journey be S1 from point A to destination and S2 from destination to point A.
So,
S1 = D/T1
then,
T1 = D/S1
Similarly,
S2 = D/T2
T2 = D/S2
Now,
Total time = T1 + T2
= (D/S1) + (D/S2)
Taking D common,
= D[(1/S1) + (1/S2)]
= D[(S1 + S2)/(S1 × S2)]
= D(S1 + S2)/(S1S2)
Now,
Avg. Speed = Total Distance/Total time
Avg. Speed = 2D/[D(S1 + S2)/(S1S2)]
Cancelling common factor D
Avg. Speed = 2/[S1 + S2)/(S1S2)]
Avg. Speed = 2 ÷ (S1 + S2)/(S1S2)
Avg. Speed = 2 × (S1S2)/(S1 + S2)
∴ Avg. Speed = 2(S1)(S2)/(S1 + S2)
So, here,
S1 = 50 km/h
S2 = 30 km/h
So,
Avg. Speed = (2 × 50 × 30)/(50 + 30)
Avg. Speed = (3000/80)
Avg. Speed = 300/8
Avg. Speed = 37.5 km/h
Hence,
Avg. Speed for the whole Journey = 37.5 km/h
Hope it helped you and believing you understood it...All the best