Physics, asked by rahuljaat5511, 6 months ago

A moves with a constant velocity u along the x axis B always have velocity towards a if a and b are inclined atban angle thetha with each other then time taken by them to meet each other is? please reply urgently.​

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Answered by saifmohammed0107
0

Answer:

formula is sin tita +cosecant tita

Answered by Amalaprincy
0

Answer:

Let at any instant the velocity of B makes an angle α with that of x-axis and the time to collide is T.

Vapp​=V−ucosα

l=∫0T​Vapp​dt

=∫0T​(V−ucosα)dt                  ...(i)

Now equating the displacement of A and B along x direction, we get

uT=∫Vcosαdt

Now from (i) and (ii), we get

l=VT−∫0T​ucosαdt

=VT−Vu​∫0T​Vcosαdt=VT−Vv​.uT

⇒T=v2−u2lV​

Now distance travelled by A and B

=u×v2−u2lV​ and v×v2−u2lV​

=V2−u2uVl​ and V2−u2V2l​

Hope it helps you,

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