A moving body in uniform acceleration for initial velocity of 10m/s and after 15 minutes it's velocity becomes 40m/s .
Find its acceleration.
Answers
Answered by
1
We know that
a=v-u/t
u=10m/s
v=40m/s
t=900sec. (Convert min into sec)
a= 40-10/900
a= 30/900
a=.033m/s square
a=v-u/t
u=10m/s
v=40m/s
t=900sec. (Convert min into sec)
a= 40-10/900
a= 30/900
a=.033m/s square
Answered by
9
✬ Acceleration = 0.003 m/s² ✬
Explanation:
Given:
- Initial velocity (u) of body is 10 m/s.
- Final velocity (v) of body is 40 m/s.
- Times taken to attain final velocity is 15 minutes.
To Find:
- What is the acceleration of body ?
Formula to be used:
- v = u + at ( First equation of motion )
Solution: Here, time is given in minutes so we need to change it into seconds.
➟ 1 minutes = 60 seconds
∴ 15 minutes = 15 60 = 900 seconds
Now, Put the values on formula.
v = u + at
40 = 10 + a 900
40 – 10 = 900a
30 = 900a
30/900 = a
0.033 m/s²
Hence, the acceleration of the body is 0.033 m/s².
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