A moving body of mass m1 strikes a stationary body of mass m2. The masses m1 and m2 shouldbe in the ratio m1/m2 so as to decrease the velocity of the first body by 1/2 in a perfectly elastic impact. What is the ratio m1/m2?
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m1v=m1v1 + m2v2 by energy conservation
1=(v1-v2)÷(-v) {by coefficient of restitution e=1)
v1=v/2 as given in the ques
so v2=(3v/2)
hence
m1v=m1v/2 +m2(3v/2)
m1=m1/2 + m2(3/2)
m1/2=m2(3/2)
m1/m2=3 .ANS. :")
1=(v1-v2)÷(-v) {by coefficient of restitution e=1)
v1=v/2 as given in the ques
so v2=(3v/2)
hence
m1v=m1v/2 +m2(3v/2)
m1=m1/2 + m2(3/2)
m1/2=m2(3/2)
m1/m2=3 .ANS. :")
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