a moving car is expericencing 100N force of wind in the opposite direction and 120N force of friction. What should be the force of engine so that the net force is 280N in the forward direction
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total force in backward direction=100+120=220N.
the net force=force in forward-force in backward.
so 280=force in forward-220
so force in forward=280+220=500N
the net force=force in forward-force in backward.
so 280=force in forward-220
so force in forward=280+220=500N
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500 Newton is the answer
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