Question

a moving coil ammeter having a full scale deflection of 10mA and a meter resistance of 2 ohms is to be converted into a voltmeterwhich can measure upto 10 v .how is this conversion achieved​

Answer 1

Answer:

To measure a high current, you put a low-resistance shunt in series with the current, and then measure the voltage drop across the shunt. Since the meter you have is 10 mV full scale, you need a shunt with a voltage drop of 10 mV at 10 A. R = E/I = 0.01/10 = 1 milliohm.

To measure a high current, you put a low-resistance shunt in series with the current, and then measure the voltage drop across the shunt. Since the meter you have is 10 mV full scale, you need a shunt with a voltage drop of 10 mV at 10 A. R = E/I = 0.01/10 = 1 milliohm.Now, that calculation really says that you want the resistance of the meter and shunt in parallel to be 1 milliohm. In this case, the resistance of the meter is 5000 times the resistance of the shunt, so it changes the total parallel resistance by only 0.02%, which can be ignored. If you wanted the full-scale current to be 100 mA or 10 mA, you would have to take the resistance of the meter coil into account in the calculations. But not at 10 A full scale.

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