A moving coil galvanometer has a resistance of 900 Ω. In order to send only 10% of the main current through this galvanometer, the resistance of the required shunt is(a) 0.9 Ω(b) 100 Ω(c) 405 Ω(d) 90 Ω
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It is option a which is 0.9ohms.
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Answer:
B) 100
Explanation:
Resistance = 900 Ω. (Given)
Current to be sent = 10% (Given)
Thus, Ig = 0.1 Is = 0.9
The voltage drop across the galvanometer when full rated current flows through is equal to -
S = Ig G/Is
= 0.1×900/0.9
= 100Ω
Thus, the resistance of the required shunt is 100Ω
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