Physics, asked by anusinghanurag7664, 1 year ago

A moving coil galvanometer has a resistance of 900 Ω. In order to send only 10% of the main current through this galvanometer, the resistance of the required shunt is(a) 0.9 Ω(b) 100 Ω(c) 405 Ω(d) 90 Ω

Answers

Answered by Toluwanimi
0

It is option a which is 0.9ohms.

Answered by Anonymous
3

Answer:

B) 100

Explanation:

Resistance = 900 Ω. (Given)

Current to be sent = 10%  (Given)

Thus, Ig = 0.1 Is = 0.9

The voltage drop across the galvanometer when full rated current flows through is equal to -

S = Ig G/Is

= 0.1×900/0.9

= 100Ω

Thus, the resistance of the required shunt is 100Ω

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