A moving coil galvanometer of resistance of resistance 20ohm products full scale deflection for a current of 50miliampere how will you convert the galvanometer into an ammeter of range 20ampere and a voltmeter of range 120volt
Answers
Given :
A moving coil galvanometer has resistance 20 ohm show full deflection for current 50mA
To Find : how to convert galvanometer to ammeter of range 20A and voltmeter of 120v
Solution :
convert galvanometer to ammeter of range 20A
Current Range can be extended using Shunt across (S)
50mA = 0.05 A
20 Ω
20 * 0.05 = 1 V
Current across Shunt = 20 - 0.05 = 19.95 A
20 * 0.05 = S * 19.95
=> S = 1/19.95
=> S = 0.05 Ω ( in Parallel)
convert galvanometer to voltmeter of 120v ( independent of 1st change)
Can be converted using High Resistance in series
High resistance must have a drop of 120 - 1 = 119V when
0.05 A current flows through it
0.05R = 119
=> R = 2380 Ω (in series)
if We need to convert it to voltmeter of 120v after converting into 20A
Then Drop of 120 -1 = 119 V is required at 20A Current Flow
20R = 119 V
=> R = 5.95 Ω (in series)
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moving coil galvanometer
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Answer:
convert galvanometer to ammeter of range 20A
Current Range can be extended using Shunt across (S)
50mA = 0.05A
20 Ω
20* 0.051 V
Current across Shunt = 200.05 = 19.95 A
20* 0.05 =S * 19.95
=> S=1/19.95.
=> S = 0.052 (in Parallel)
convert galvanometer to voltmeter of 120v (independent of 1st change)
Can be converted using High Resistance in series
High resistance must have a drop of 120 -1 = 119V when
0.05 A current flows through it,
0.05R = 119
=> R=2380 (in series)
if We need to convert it to voltmeter of 120v after converting into 20A
Then Drop of 20 - 1 = 119V is required at 20A Current Flow
2OR = 119V
=> R= 5.95 (in series).