A moving train is brought to rest within 20sec by applying breaks. Find the initial velocity, if the retardation due to break 2meater/second?
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Answered by
382
Let, u be the initial velocity
Retardation is a Time is t
Velocity is v
We know, v = u + at
As, the train stops so v = 0 Time t = 20s
Retardation a = 15m/s
Therefore, according to the formula u = 0 + (15*20) = 300 m/s.
Retardation is a Time is t
Velocity is v
We know, v = u + at
As, the train stops so v = 0 Time t = 20s
Retardation a = 15m/s
Therefore, according to the formula u = 0 + (15*20) = 300 m/s.
Answered by
6
Answer:
Given:
Final velocity v = 0
Time taken t = 20 s
Acceleration a = -2 m/s2
From the equation v = u + at, we have
u = v - at
→ u = 0 - (-2) × 20
→ u = 40 m/s2
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