A myopic person uses specs of power -1.6 D. What is the distance of far point of his eye.
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Answer:
Explanation:
if a person is suffering from myopia .. his far point is less than infinty.. as the image is formed in front of retina.
power of the spects = -1.6 D
we have,
P = 1/ F
-1.5 = 1/ F
F = -1/ 1.5
F = -10/ 15
THEREFORE, F = -0.67
this states that his focal length is -0.67m .
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