Question

find the sum of first 16 terms of AP whose first term is 4 and common difference is -3?​

Answer 1

Step-by-step explanation:

first term=4

common difference=-3

then,

S16=?

solution,

S16=n/2[2a+(n-1)d]

= 16/2[2*4+(16-1)-3]

=8[8+15*(-3)]

= 8[8-45]

= 8*(-37)

= -296

S16 =-296