A(n)equal (n-1)(n-2)(n-3)show that the first terms of the sequence are zero,but the rest of the terms are positive
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(1-1)(1-2)(1-3) =0
(2-1)(2-2)(2-3)=0
(3-1)(3-2)(3-3)=0
(4-1)(4-2)(4-3)=(3)(2)(1)=6....ans so on
Tn =
n= 1,2,3,4,5,6....so on
first three gives 0 but 3< n gives always positive natural number
HP.
(2-1)(2-2)(2-3)=0
(3-1)(3-2)(3-3)=0
(4-1)(4-2)(4-3)=(3)(2)(1)=6....ans so on
Tn =
n= 1,2,3,4,5,6....so on
first three gives 0 but 3< n gives always positive natural number
HP.
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