Chemistry, asked by susuki7145, 11 months ago

A n object of size 7cm is placed at a distance of 27cm in front of a concave mirror of focal length 18cm

Answers

Answered by jumaanhussein11
5

Answer:

Explanation:

Height of the object is (ho) 7cm

Object distance (u)=27cm

Focal length (f)=18cm

Image distance (v)=required

Height of the image (hi)=required

From,

1/f=1/u+1/v

1/18=1/27+1/v

1/18=v+27/27v

27v=18(v+27)

27v=18v+486

(27-18)v=486

9v=486 divide by 9 both sides

v=486/9

v=54cm

The image distance is 54cm

Again from,

v/u=hi/ho

54/27=hi/7

27hi=57×7

27hi=399. Divide by 27 both sides

hi=399/27=14•777777778cm

hi=14•778cm

And also,

M=v/u

M=54/27

M=2 M=magnification

Hope it's helpful

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