Question

A na B ni seti mbili zenye kikomo, ambapo n(A)=20 n(B)=28 na n(AuB)=36. Tafuta n(AnB)

Answer 1

here,
n(A)=20
n(B)=28
n(AUB)=36
so,
n(AUB) = n(A)+n(B)-n(AΠB)
n(AΠB) = n(A)+n(B)-n(AUB) = 20+28-36 = 48-36 = 12
so,
n(AΠB)=12