a natural number a is multiplied by 11 and 33 is added to it and when it is divided by 9 the remainder is zero then the sum of all such two digit numbers a is
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18
Answer:
555
Step-by-step explanation:
number=ax11+33
=11(a+3)
when it is divided by 9
11/9(a+3) the remainder is 0
therefore a+3 should a 2 digit number divisible by 9
possible values of a=15,24,33,42,51,60,69,78,87,96
therefore on adding these values,
the answer = 555
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