a natural number is divisible by 1125,which consist only 0 and 1 .minimum how many 0 and 1 are there in such number?
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i dont really know the answer
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given that 1125= 5^3 * 3^2
as we know, a number to be divisible by 1125 must end with three 0s, also a number to be divisible by 3^2 must have the sum of all its digits divisible by 9. so we can deduce, the number has to contain nine 1s. and be ended by three 0s, therefore the required number must have three 0s and nine 1s.
option D is correct
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