Question

A natural number when increased by 12 then its reciprocal becomes 160 times. What is the number?

Answer 1

Hi,

Let The Natural Number = C

If The Number Increased By 12 = X + 12

Reciprocal Of The Number = 1/X

According To The Problem Given,

X + 12 = 160 Times Of Reciprocal Of X

X + 12 = 160/ X

X( X + 12 ) = 160

X^2 + 12x - 160 = 0

X^2 + 20x - 8x - 160 = 0

X( X + 20) - 8( X + 20)= 0

( X + 20 ) ( X - 8 ) = 0

X + 20 = 0 Or X - 8 = 0

X = - 20 Or X = 8

But X Is A Natural Number.

Therefore,

Required Number = X = 8

I Hope This Helps You.

:)

Mark It Brainleist.

Answer 2

Answer:

Step-by-step explanation:

Let the natural no. = x

A. T. Q

x + 12 = 160*1/x

x*x + 12x = 160

x*x + 12x - 160 = 0

x*x + 20x - 8x -160 =0

x(x + 20)-8(x + 20) = 0

(x+20) (x-8)

x = 8

The number is 8