A nearsighted student has a near point of 0.1 m and focal length of 5 cm. What is the student's far point?
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Answer: 0.1m
Explanation:
The person's image distance v will be at the distance of 0.1m = 10cm for him to see objects at a distance of u.
F = 5.0cm
According to mirror formula,
1/v+1/u=1/f
⟹1/10+1/u=1/5
1/u=1/5−1/10
1/u=(2−1)/10
1/u=1/10
therefore u=10cm=0.1m
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