Question

A necklace was broken during an amorous
struggle. 1/3rd of the pearls fell to the ground.
1/5th stayed on the couch, 1/6th were found by the
girl, and 1/10th recovered by her lover; six pearls
remained on the string. Say of how many pearls the
necklace was composed
ained​

Answer 1

Answer:

30 pearls

Step-by-step explanation:

Let no of pearls be x.

Then,

no of pearls lost is:

($\frac{1}{3}$+$\frac{1}{5}$+$\frac{1}{6}$+$\frac{1}{10}$)x

Taking LCM=30,

$\frac{10+6+5+3}{30}$=$\frac{24x}{30}$

Then no of pearls left = $\frac{6x}{30\\}$=$\frac{1x}{5}$=6(Given)

Therefore x = 6*5=30