Question

A neon-dioxygen mixture contains 70.6 g
dioxygen and 167.5g neon.If pressure of
the mixture of the gases in the cylinder
is 25 bar. What is the partial pressure of
dioxygen and neon in the mixture?

Answer 1

Answer:

Explanation:

(Partial pressure is equal to mole fraction of given gas x pure pressure). (also mole fraction is equal to number of moles of given gas present per total number of Moles). (Moles of dioxygen in mixture is equal to given mass of dioxygen /molecular mass of dioxygen), [hance mole of dioxygen in mixture is equal to 70.6 gram / 32 gram equal to 2.2 moles]. {Moles of neon in mixture equal to given mass of neon / atomic mass of neon equal to 167.5 gram / 20=8.3 moles, total number of Moles=2.2 + 8.3=10.5 Mole

Mole fraction of O2=2.2/10.5=0.2 and mole fraction of neon is equal to 8.3/10.5=0.8; partial pressure of oxygen=0.2 x 25=5 bar, partial pressure of neon=0.8 x 25=20 bar}