Question

a net force of 10N acts on 2kg object.Calculate the distance travelled by the object in 5s

Answer 1

Answer:

62.5 m

Explanation:  

F = ma      ⇒ 10 = 2m    ⇒ 5 = m

Acceleration of the object is 5 m/s².

  Using the equation of motion: if the object was at rest

⇒ S = ut + 1/2 at²

⇒ S = (0)t + 1/2 (5)(5)²

⇒  S = 62.5 m

Distance travelled by the object is 62.5 m

Answer 2

F = ma

$10 = 2m \\ \\ m = \frac{10}{2} \\ \\ m = 5$

• Acceleration of object = 5 m/s².

object.Calculate the distance travelled by the object in 5s :-

S = (0) t + 1/2 (5) (5) ²

S = ut + 1 / 2 at²

= 62.5m Answer

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hope it helps