a net force of 20 N acts on a 5 kg mass kept at rest. What id the distance traveled by the mass in 6 second?
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Hi friend,
We know that ,
F= ma
a=F/m
a= 4m/s².
We know that v= u+at
Here the initial velocity is at rest.
V= 4×6
V= 24 m/s.
Distance travelled (s) = ut +1/2 at² .
s= 1/2 ×4 ×36 S= 72 m.Hope this helped you a little!!!
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