Question

a net force of 20 N acts on a 5 kg mass kept at rest. What id the distance traveled by the mass in 6 second?

Answer 1

Hi friend,

We know that ,

F= ma 

a=F/m

a= 4m/s².

We know that v= u+at

Here the initial velocity is at rest.

V= 4×6 

V= 24 m/s.

Distance travelled (s) = ut +1/2 at² .

s= 1/2 ×4 ×36 S= 72 m.Hope this helped you a little!!!

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