Question

A net force of 20 New acts on a 5 kg mass kept at rest. Distance travelled by the mass in 6 s is

Answer 1

Hi there !

Force = F = 20 N

Mass = m = 5kg

Time = t = 6 sec

Initial velocity = u = 0

Force = Mass x acceleration

acceleration = a = force / mass
= 20 / 5
= 4 m/s²

Equation of motion :-

distance traveled = s

s = ut +1/2at²
= 0 + 1/2 × 4 × 6 × 6
= 72 metre

Answer 2

AnswEr:-

$\huge{ \blue{ \mathfrak{Hello \:Mate}}}$

Given,

Force, F = 20 N

Mass, m = 5 Kg

Time, t = 6 sec

Initial velocity, u = 0 m/s

We know that,

Force = Mass × Acceleration

or, Acceleration, a = (Force/Mass) m/s²

= (20/5) m/s²

= 4 m/s²

So, distance travelled = s

∴ s = (ut + ½at²) m

= (0 + ½ × 4 × 6 × 6) m

= (2 × 36) m

= 72 m

$\huge{ \boxed{ \red{ \mathfrak{Answer = 72 \: metre }}}}$