Physics, asked by mahithshashank, 8 months ago

a neutral conducting spherical shell is kept near a charge q. the potential at point P due to the induced charges is?​

Answers

Answered by arenarohith
2

Answer:

Let potential due to induced charged=Vin

As the field is zero inside the conductor, potential will be constant and same as point on the surface.​

Vp=ka /r'+ V in= Vc =kq /r ×VIn=kq/r−kq/r'

Answered by OOOIRKIOOO
3

Answer:

Let potential due to induced charged=V_{in}

Potential at P,V_{P} = \frac{kq}{r'} + V_{in}

​Potential at C,V_{c} = \frac{kq}{r}

As the field is zero inside the conductor, potential will be constant and same as point on the surface.

so, V_{P} = V_{C}

\frac{kq}{r'} + V_{in} = \frac{kq}{r}

V_{in} = \frac{kq}{r} - \frac{kq}{r'}

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