Question

a neutron if mass 1.67X10^-27 kg is moving with speed 7X10^5 m/s
a) find kinetic energy average force
b) average force it will exert on entering the body of depth 0.01 cm
ans) 40.915×10^-17 J, 40.915×10^-13 N

Answer 1

Answer:

In Electrostatics Coulomb give a formula of magnitude of force acting between two system of charges and was given by

s

Answer 2

Answer:

a) 4.067*10^-16J

Explanation:

KE=1/2 mv^2

m=1.67*10^-27kg

v= 7*10^5m/s

applying the formula,we get

KE= 4.067*10^-16J